\begin{question}{q1}
Calculate the $\Delta E$ for an electron transitioning from the HOMO to the LUMO for a dye called 3,3$^\prime$-diethylthiapentacarbocyanine iodide. (The number of significant figures are not critical.)
\begin{multicols}{5}
\AMCBoxedAnswers
\begin{choices}
\wrongchoice{5.4$\times10^{-19}$ J}\scoring{0} %for dicarbo
\wrongchoice{2.9$\times10^{-19}$ J}\scoring{0}%made up answer
\wrongchoice{2.7$\times10^{-18}$ J}\scoring{5}%off by order of magnitude
\wrongchoice{5.4$\times10^{-18}$ J}\scoring{0}% dicarbo, off by order of mag.
\correctchoice{2.7$\times10^{-19}$ J}\scoring{10}
\end{choices}
\end{multicols}
\end{question}


\begin{question}{q2}
Identify the correct way to complete this statement: As the length of the conjugated chain decreases,

%\begin{multicols}{5}
\AMCBoxedAnswers
\begin{choices}
%\wrongchoice{}\scoring{0}
\correctchoice{the HOMO-LUMO gap increases and the percent error of the calculated value increases.}\scoring{10}
\wrongchoice{the HOMO-LUMO gap increases and the percent error of the calculated value decreases.}\scoring{5}%half right
\wrongchoice{the HOMO-LUMO gap decreases and the percent error of the calculated value increases.}\scoring{5}%half right
\wrongchoice{ the HOMO-LUMO gap decreases and the percent error of the calculated value decreases.}\scoring{0} %neither is true
\end{choices}
%\end{multicols}
\end{question}


\begin{question}{q3}
Identify the correct formula for the energy of the HOMO-LUMO gap in terms of $N$, the total number of $\pi$-electrons confined to a conjugated chain.
\begin{multicols}{2}
\AMCBoxedAnswers
\begin{choices}
\wrongchoice{$\displaystyle \Delta E=\frac{Nh^2}{8mL^2}$\\}\scoring{0}
\wrongchoice{$\displaystyle \Delta E=\frac{3N^2h^2}{32mL^2}$\\}\scoring{0}
\wrongchoice{$\displaystyle \Delta E=\frac{(N+1)h^2}{32mL^2}$\\}\scoring{0}
\wrongchoice{$\displaystyle \Delta E=-\frac{(N+1)h^2}{8mL^2}$\\}\scoring{5}%LUMO-HOMO gap (backwards)
\correctchoice{$\displaystyle \Delta E=\frac{(N+1)h^2}{8mL^2}$\\}\scoring{10}
%\wrongchoice{None of these.}\scoring{0}
\end{choices}
\end{multicols}

\end{question}